minS=4X1 5X1 6X3

!紧急求助!（运筹学）用两阶段法求两道解线性规划~~急!谢谢了~!maxS=X1+X2s.t.X1+X2>=1X1-X2>=0X1>=0,X2>=0minS=4X1+5X1+6X3(中间的叉不是乘号,

用初等行变换来解下列线性方程组（1）2x1-x2+3x3=33x1+x2-5x3=04x1-x2+x3=3x1+3x2-13x3=-6(2)x1-2x2+x3+x4=1x1-2x2+x3-x4=-1x

解线性方程组x1+x2+3x3+4x4=52x1+4x2+4x3+6x4=8-x1-2x2-x3-2x4=-3解线性方程组x1+x2+3x3+4x4=52x1+4x2+4x3+6x4=8-x1-2x2

求解线性方程组X1+X2+X3=62X1+3X2+X3=11X1-X2+2X3=5求解线性方程组X1+X2+X3=62X1+3X2+X3=11X1-X2+2X3=5求解线性方程组X1+X2+X3=62

解线性方程组x1-x2-x3=2x1+x2+4x3=03x1+5x3=3解线性方程组x1-x2-x3=2x1+x2+4x3=03x1+5x3=3解线性方程组x1-x2-x3=2x1+x2+4x3=03

求解齐次线性方程组2x1+3x2-x3-7x4=03x1+x2+2x3-7x4=04x1+求解齐次线性方程组2x1+3x2-x3-7x4=03x1+x2+2x3-7x4=04x1+x2-3x3+6x4

maxZ=2X1+4X2-5X3X1+X2+X3=72X1-3X2+X3≥10X1.X2.X3≥0maxZ=2X1+4X2-5X3X1+X2+X3=72X1-3X2+X3≥10X1.X2.X3≥0ma

｛2X1-X2+3X3=33X1+X2-5X3=04X1-X2+X3=3X1+3X2-13X3=-6{X1-2X2+3X3-4X4=4X2-X3+X4=-3X1+3X2-3X4=1-7X2+3X3+X

求线性方程组2x1+3x2+x3=4;x1-2x2+4x3=-5;3x1+8x2-2x3=13;4x1-x2+9x3=-6的全部解求线性方程组2x1+3x2+x3=4;x1-2x2+4x3=-5;3x

运筹学线性规划化标准型目标函数：minz=x1-x2-x3+2x4约束条件：10x1+x2-x3-4x4=77x1+6x2-2x3-5x4>=104x1-8x2+6x3+x4运筹学线性规划化标准型目标

线性方程组求解2x1-x2+3x3=33x1+x2-5x3=04x1-x2+x3=3x1+3x2-13x3=-6线性方程组求解2x1-x2+3x3=33x1+x2-5x3=04x1-x2+x3=3x1

线性方程组求解2x1-x2+3x3=33x1+x2-5x3=04x1-x2+x3=3x1+3x2-13x3=-6用矩阵的方法线性方程组求解2x1-x2+3x3=33x1+x2-5x3=04x1-x2+

矩阵线性方程组2x1-x2+3x3=33x1+x2-5x3=04x1-x2+x3=3x1+3x2-13x3=-6用消元法怎么计算呢.请需要帮助.矩阵线性方程组2x1-x2+3x3=33x1+x2-5x

已知数据3,x1,2,4,x2,5,x3,6的平均数是5,那么x1+x2+x3=.已知数据3,x1,2,4,x2,5,x3,6的平均数是5,那么x1+x2+x3=.已知数据3,x1,2,4,x2,5,

求解齐次线性方程组2x1+3x2-x3-7x4=03x1+x2+2x3-7x4=04求解齐次线性方程组2x1+3x2-x3-7x4=03x1+x2+2x3-7x4=04x1+x2-3x3+6x4=0x

解方程组x1+x2=4,x2+x3=-6,x3+x1=2解方程组x1+x2=4,x2+x3=-6,x3+x1=2解方程组x1+x2=4,x2+x3=-6,x3+x1=2x1+x2=4①x2+x3=6②

写出对偶规划X1+5X2-3X3>=15-5X1-6X2+10X3写出对偶规划X1+5X2-3X3>=15-5X1-6X2+10X3写出对偶规划X1+5X2-3X3>=15-5X1-6X2+10X3目

求下面线性规划问题的对偶问题minZ--x1+3x2-5x3-2x1+6x2-x3≥30X1+4x2-3x3≤20X1-x2+x3--4X1≤0,x2≥0,x3无约束求下面线性规划问题的对偶问题min

matlab解线性方程组请问,13x1=2x1+x2+6x3+4x413x2=4x1+3x2+2x3+3x413x3=2x1+5x2+3x3+3x413x4=5x1+4x2+2x3+3x4这个方程组用

求下列非齐次线性方程组的通解(1)｛x1+x2+x3+x4+x5=2；x1+2x2-4x5=-2；x1+2x3+2x4+6x5=6；4x1+5x2+3x3+3x4-x5=4｝(2)｛x1-x2+5x3