化简sin(-α-5π)*cos(α-π/2)-tan(α-3π/2)*tan(2π-α)

化简:(sin(α-3π)*cos(-α))/(tan(α-5π)*cos^2(α-5π)*tan(4π-α))化简:(sin(α-3π)*cos(-α))/(tan(α-5π)*cos^2(α-5π

化简cos(α-π)tan(α-2π)tan(2π-α)/sin(π+α)化简cos(α-π)tan(α-2π)tan(2π-α)/sin(π+α)化简cos(α-π)tan(α-2π)tan(2π-

cos(π-α)tan(2π-α)tan(π-α)/sin(π+α)化简cos(π-α)tan(2π-α)tan(π-α)/sin(π+α)化简cos(π-α)tan(2π-α)tan(π-α)/si

sin(2π-α)tan(α+3π)tan(-α-π)/tan(α-3π)cos(π-α)sin(2π-α)tan(α+3π)tan(-α-π)/tan(α-3π)cos(π-α)sin(2π-α)t

化简：[sin(π+α)*cos(π-α)*tan(π-α)]/[cos(π/2+α)*tan(3π/2-α)*tan(α-3π)]化简：[sin(π+α)*cos(π-α)*tan(π-α)]/[c

化简sin(3π-α)/[sin(-α-2π)]+cos(4π-α)/[cos(α-5π)]+tan(-α)/[tan(π+α)]化简sin(3π-α)/[sin(-α-2π)]+cos(4π-α)/

化简[sin²(α+π)cos(α+π)]/tan(α+π)cos³(-α-π)tan(-α-2π)化简sin²(α+π)cos(α+π)/tan(α+π)cos

化简:cos(2π-α)sin(-π-α)/sin(π/2+α)tan(3π-α)化简:cos(2π-α)sin(-π-α)/sin(π/2+α)tan(3π-α)化简:cos(2π-α)sin(-π

化简cos(α-π)sin²(α+2π)/tan(α+4π)tan(α+π)cos³(-α-π)化简cos(α-π)sin²(α+2π)/tan(α+4π)tan(α+π

若a属于(0,π/2)试比较tanα、tan(tanα)、tan(sinα)若a属于(0,π/2)试比较tanα、tan(tanα)、tan(sinα)若a属于(0,π/2)试比较tanα、tan(t

计算sin(-α-5π)*cos(α-2分之π)-tan(α-2分之3π)*tan(2π-α)计算sin(-α-5π)*cos(α-2分之π)-tan(α-2分之3π)*tan(2π-α)计算sin(

1.求证tanαsinα/tanα-sinα=tanα+sinα/tanαsinα2.已知sinα+cosα=-1/5(π/21.求证tanαsinα/tanα-sinα=tanα+sinα/tanα

化简sin(9π+α）tan（3/2π+α）/cos(-4π-α）tan（15π+α）tan(7/2π-α）化简sin(9π+α）tan（3/2π+α）/cos(-4π-α）tan（15π+α）tan

已知3sinα+5cosα=5,求3cosα-5sinα第二题化简根号[1-2tan(-37π/6)+tan²(-43π/6)]第三题已知[1-tan(π-α)]/[1-tan(π+α)=3

tan(π-α)*sin^2(α+π/2)*cos(2π-α)/cos^3(-α-π)*tan(2π-α)sin^2就是sin的平方,下同tan(π-α)*sin^2(α+π/2)*cos(2π-α)

化简[tan(2π-α)sin(-2π-α)cos(6π-α)]/[cos(α-π)sin(5π-α)]化简[tan(2π-α)sin(-2π-α)cos(6π-α)]/[cos(α-π)sin(5π

化简tan(2π-α)sin(-2π-α)cos(6π-α)/cos(α-π)sin(5π-α)化简tan(2π-α)sin(-2π-α)cos(6π-α)/cos(α-π)sin(5π-α)化简ta

化简sin(π/2+α)cos(3π-α)tan(π+α)/cos(π/2-α)cos(-α-π)化简sin(π/2+α)cos(3π-α)tan(π+α)/cos(π/2-α)cos(-α-π)化简

化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π

化简[sin(π-α)cos(3π-α)tan(-α-π)]/[tan(4π-α)sin(5π+α)]化简[sin(π-α)cos(3π-α)tan(-α-π)]/[tan(4π-α)sin(5π+α