9(x+3)²-16(x+2)²=0怎么解?

9(x+3)²-16(x+2)²=0怎么解?
9(x+3)²-16(x+2)²=0怎么解?

9(x+3)²-16(x+2)²=0怎么解?
9(x+3)²-16(x+2)²=0
[3(x+3)+4(x+2）][3(x+3)-4(x+2)]=0
(7x+17)(-x+1)=0
x1=-17/7,x2=1

9（x+3）^2=16((x+2)^2
3(x+3)=4(x+2) -3(x+3)=4(x+2)
x=1, -17/7,

x=17 9(x+3)²-16(x+2)²=0
3^2(x+3)^2-4^2(x+2)^2=0
3(x+3)-4(x+2)=0
3x+9+-4x-8=0
-x+1=0
-x=-1
x=1