已知x+2y=11,x-2y=4,求分式[x/(x^2-2xy+y^2)]÷(x^2+xy+y^2)/(x^3-y^3)+[(2x+2y)/(x-y)-2]的值⊙ o ⊙

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已知x+2y=11,x-2y=4,求分式[x/(x^2-2xy+y^2)]÷(x^2+xy+y^2)/(x^3-y^3)+[(2x+2y)/(x-y)-2]的值⊙o⊙已知x+2y=11,x-2y=4,

已知x+2y=11,x-2y=4,求分式[x/(x^2-2xy+y^2)]÷(x^2+xy+y^2)/(x^3-y^3)+[(2x+2y)/(x-y)-2]的值⊙ o ⊙
已知x+2y=11,x-2y=4,求分式[x/(x^2-2xy+y^2)]÷(x^2+xy+y^2)/(x^3-y^3)+[(2x+2y)/(x-y)-2]的值
⊙ o ⊙

已知x+2y=11,x-2y=4,求分式[x/(x^2-2xy+y^2)]÷(x^2+xy+y^2)/(x^3-y^3)+[(2x+2y)/(x-y)-2]的值⊙ o ⊙
神!自己慢慢算.
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