3[(Y+3)/2]+2Y=8
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3[(Y+3)/2]+2Y=83[(Y+3)/2]+2Y=83[(Y+3)/2]+2Y=83[1/2y+3/2]+2y=83/2y+9/2+2y=87/2=7/2y=1y=1
3[(Y+3)/2]+2Y=8
3[(Y+3)/2]+2Y=8
3[(Y+3)/2]+2Y=8
3[1/2y+3/2]+2y=8
3/2y+9/2+2y=8
7/2=7/2
y=1
y=1
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