过点A(4,-1)和双曲线x^2/9-y^2/16=1右焦点的直线方程

过点A(4,-1)和双曲线x^2/9-y^2/16=1右焦点的直线方程
过点A(4,-1)和双曲线x^2/9-y^2/16=1右焦点的直线方程

过点A(4,-1)和双曲线x^2/9-y^2/16=1右焦点的直线方程
令坐标a(x,y),b(x,y)则有:x^/9-y^/=;x^/9-y^/=;两式相减得:(x+x)(x-x)/9=(y+y)y0=(y+y)/;则 y0=x0.由弦ab过右焦点f(,0)可知直线ab方程为y=x-;则有:y0=x0-;与y0=x0联立解得:x0=-/;