y=2sin(2x+π/3),x属于-6分之派到6分之派,求值域
来源:学生作业帮助网 编辑:六六作业网 时间:2025/02/02 14:58:49
y=2sin(2x+π/3),x属于-6分之派到6分之派,求值域y=2sin(2x+π/3),x属于-6分之派到6分之派,求值域y=2sin(2x+π/3),x属于-6分之派到6分之派,求值域1,
y=2sin(2x+π/3),x属于-6分之派到6分之派,求值域
y=2sin(2x+π/3),x属于-6分之派到6分之派,求值域
y=2sin(2x+π/3),x属于-6分之派到6分之派,求值域
1,
y=2sin(x/2+π/6),x属于R y=-6sin(2x-π/3),x属于R 写出振幅,周期,初相
求下列函数周期 y=3sin(x/4) x属于Ry=2sin(2x-π/6)
y=sin(2x+π/6),x属于[π/6,3π/4],求值域
1.y=sin(1/2x+π/6),x属于[0,π/3] 2.y=-cos(3x-π/3),x属于[-π/3,π/3]
函数y=2sin((π/3)-x)-cos((π/6)+x) (x属于R)的最小值是
函数y=2sin(x/3+π/3)[x属于(-π,-π/2)]的值域
y=2sin[(π/6)-2x]的单调递增区间 x属于[0,π]
函数y=sin(x+π/6),x属于【0,π/2】的值域是?
求三角函数值域 y=sin(2x-派/3),x属于[派/6,派/2]
求下列函数的值域:(1)y=sin(2x-π/6)-1/2,x属于[0,2π/3](2)y=2sin^2x+2sinx-1/2,x属于[π/6,5π/6]
函数y=3sin(2x+π/6)(x属于[0,π])的减区间?函数y=3sin(2x+π/6)(x属于[0,π])的减区间?
求下列的函数周期(1)y=3sinx,x属于R (2)y=cos2x,x属于R (3)y=2sin(1/2x-π/6),x属于R
作出y=3sin(2x+π/6),x属于R图像和y=3sin(2x+π/6),x属于R的图像,麻烦带上图像,如题
已知函数y=2sin(3x+π/3),x属于R当x属于[-2π/9,π/6]时,求函数的最大值与最小值
求函数y=2sin(2x+π/3),x属于(-π/6,π/6)的值域要过程
求函数y=2sin(2x+π/3),x属于(-π/6,π/6)的值域
函数y=2sin(x+π/3),x属于[π/6,π/2]的值域
y=sin(1/2x-π/6) x属于 [-π/3,-π ]的定义域 要完整的步骤