已知(x+y)(y+z)(z+x)=0,xyz不等于0 求证:1/x+1/y+1/z=1/(x+y+z)
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已知(x+y)(y+z)(z+x)=0,xyz不等于0求证:1/x+1/y+1/z=1/(x+y+z)已知(x+y)(y+z)(z+x)=0,xyz不等于0求证:1/x+1/y+1/z=1/(x+y+
已知(x+y)(y+z)(z+x)=0,xyz不等于0 求证:1/x+1/y+1/z=1/(x+y+z)
已知(x+y)(y+z)(z+x)=0,xyz不等于0 求证:1/x+1/y+1/z=1/(x+y+z)
已知(x+y)(y+z)(z+x)=0,xyz不等于0 求证:1/x+1/y+1/z=1/(x+y+z)
因为(x+y)(y+z)(z+x)=0,因此x+y=0或者y+z=0或者z+x=0
又因为xyz不等于0 ,因此x,y,z均不为零
当x+y=0时 x=-y;1/x+1/y = 0;1/(x+y+z) = 1/z;等式成立
同理其他情况下等式也成立
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