已知a-b=1,a²+b²=13,求(a三次方-2*b三次方)-(a²b-2ab²)-(ab²-b三次方）的值

已知a-b=1,a²+b²=13,求(a三次方-2*b三次方)-(a²b-2ab²)-(ab²-b三次方）的值
已知a-b=1,a²+b²=13,求(a三次方-2*b三次方)-(a²b-2ab²)-(ab²-b三次方）的值

已知a-b=1,a²+b²=13,求(a三次方-2*b三次方)-(a²b-2ab²)-(ab²-b三次方）的值
原式=a³-2b³-a²b+2ab²-ab²+b³
=a³-a²b+ab²-b²
=a²(a-b)+b²(a-b)
=(a-b)(a²+b²)
=1×13
=13