(3x-³y-²)²÷9×﹙⅓x²y-¹﹚³

(3x-³y-²)²÷9×﹙⅓x²y-¹﹚³
(3x-³y-²)²÷9×﹙⅓x²y-¹﹚³

(3x-³y-²)²÷9×﹙⅓x²y-¹﹚³
[3x^(-3)y^(-2)]^÷9×[(1/3)x^y^(-1)]^3
=9x^(-6)y^(-4)÷9×（1/27）x^6y^(-3)
=(1/27)y^(-7).