若x²-6x²+11x-6=(x-1)(x²+mx+n),求m,n的值

若x²-6x²+11x-6=(x-1)(x²+mx+n),求m,n的值
若x²-6x²+11x-6=(x-1)(x²+mx+n),求m,n的值

若x²-6x²+11x-6=(x-1)(x²+mx+n),求m,n的值
x³-6x²+11x-6
=x³-x²-5x²+5x+6x-6
=x²(x-1)-5x(x-1)+6(x-1)
=(x-1)(x²-5x+6)
∴m=-5
n=6