[(x+y)²-(x-y)]²÷2xy
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[(x+y)²-(x-y)]²÷2xy[(x+y)²-(x-y)]²÷2xy[(x+y)²-(x-y)]²÷2xy[(x+y)²-
[(x+y)²-(x-y)]²÷2xy
[(x+y)²-(x-y)]²÷2xy
[(x+y)²-(x-y)]²÷2xy
[(x+y)²-(x-y)]²÷2xy
=(x+y+x-y)(x+y-x+y)÷2xy
=4xy÷2xy
=2
如追加其它问题,
[(x+y)²-(x-y)²]÷2xy
=[(x²+2xy+y²)-(x²-2xy+y²)]÷2xy
=4xy/2xy
=2
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