若|3a+2b+3|+(b-3)^2=0,则a+b=
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若|3a+2b+3|+(b-3)^2=0,则a+b=若|3a+2b+3|+(b-3)^2=0,则a+b=若|3a+2b+3|+(b-3)^2=0,则a+b=3a+2b+3=0,b-3=0b=3a=-9
若|3a+2b+3|+(b-3)^2=0,则a+b=
若|3a+2b+3|+(b-3)^2=0,则a+b=
若|3a+2b+3|+(b-3)^2=0,则a+b=
3a+2b+3=0,b-3=0
b=3 a=-9
a+b=-6