xy(xy+1)+(xy+3)-2(x+y+2分之一）-(x+y-1)的平方进行因式分解
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xy(xy+1)+(xy+3)-2(x+y+2分之一）-(x+y-1)的平方进行因式分解xy(xy+1)+(xy+3)-2(x+y+2分之一）-(x+y-1)的平方进行因式分解xy(xy+1)+(xy
xy(xy+1)+(xy+3)-2(x+y+2分之一）-(x+y-1)的平方进行因式分解
xy(xy+1)+(xy+3)-2(x+y+2分之一）-(x+y-1)的平方
进行因式分解
xy(xy+1)+(xy+3)-2(x+y+2分之一）-(x+y-1)的平方进行因式分解
xy(xy+1)+(xy+3)-2(x+y+1/2)-(x+y-1)^2
=xy(xy+1)+(xy+1)+2-2(x+y)-1-[(x+y)^2-2(x+y)+1]
=(xy+1)^2+2-2(x+y)-1-(x+y)^2+2(x+y)-1
=(xy+1)^2-(x+y)^2
=(xy+x+y+1)(xy-x-y+1)
=(x+1)(y+1)(x-1)(y-1)
原式=xy(xy+1)+{(xy+1)+2}-{2(x+y)+1}-{(x+y)-1}^2
=xy(xy+1)+(xy+1)+2-2(x+y)-1-{(x+y)^2-2(x+y)+1}
=(xy+1)(xy+1)-2(x+y)-(x+y)^2+2(x+y)
=(xy+1)^2-(x+y)^2
(-3xy+2xy)-(4xy+xy)
3xy(x^2-xy^2+xy)-xy^2(2x^2-xy+2x)
2x²y-3(2xy-xy)-xy
1-(3xy-x)+【-2(2x+3xy)】
计算3xy[2xy-x(y-2)+x-1]
因式分解X^3-2xy+xy^2
已知（x+1）*（x+1）=-Iy-1I,求2（xy-（5xy）*（5xy））-3（（xy）*（xy）-xy）
【x(xy-xy)-y(x-xy)】÷3xy
当x=3,y=3分之1时,求代数出3xy-[2xy-2(xy-2分之3xy)+xy]+3xy的值
(-xy^-1)^2*(-xy^-2)^-3/(-x^2y^3)
( )-(x^2+3xy)=-xy-1/3y^2
y^3+xy^2+2xy+x^2-1 因式分解
5x^2y/-1/2xy*3xy^2
xy(xy+1)+xy+3-2(x+y+1/2)-(x+y-1)^2因式分解
(-1/3xy)^2•[xy(2x-y)-2x(xy-y^2)]
(-3分之1xy)的平方×[xy(2x-y)-2x(xy-y的平方)]
XY(XY+3)+(XY+4)+4(X+Y+1)-(X+Y+2)
5xy^2-{2x^y-[3xy^2-（xy^2-2x^2y）]/（-1/2xy）}