Y=√x2-3+√5-x2/x+2求定义域.

来源：学生作业帮助网编辑：六六作业网时间：2025/01/04 00:30:44

Y=√x2-3+√5-x2/x+2求定义域.Y=√x2-3+√5-x2/x+2求定义域.Y=√x2-3+√5-x2/x+2求定义域.Y=√x2-3+√5-x2/x+2x^2-3>=05-x^2>=0x

Y=√x2-3+√5-x2/x+2求定义域.
Y=√x2-3+√5-x2/x+2求定义域.

Y=√x2-3+√5-x2/x+2求定义域.
Y=√x2-3+√5-x2/x+2
x^2-3>=0
5-x^2>=0
x+2≠0
解得-√5