1.Find a sequence of transformations which transforms the graph of y=loge (x) （以e为底x的对数）to the graph of y=-2loge (2-x) (打不出来和上边一样 见谅).2.Sketch the graph of y=-2loge (2-x)3.Solve the equation -2loge (2-x)=10 for x

1.Find a sequence of transformations which transforms the graph of y=loge (x) （以e为底x的对数）to the graph of y=-2loge (2-x) (打不出来和上边一样 见谅).2.Sketch the graph of y=-2loge (2-x)3.Solve the equation -2loge (2-x)=10 for x
1.Find a sequence of transformations which transforms the graph of y=loge (x) （以e为底x的对数）to the graph of y=-2loge (2-x) (打不出来和上边一样 见谅).
2.Sketch the graph of y=-2loge (2-x)
3.Solve the equation -2loge (2-x)=10 for x

1.Find a sequence of transformations which transforms the graph of y=loge (x) （以e为底x的对数）to the graph of y=-2loge (2-x) (打不出来和上边一样 见谅).2.Sketch the graph of y=-2loge (2-x)3.Solve the equation -2loge (2-x)=10 for x
1.a) x--> -x
b).-x ---> -x+2 (2-x)
c).flip the whole graph and double the y-coordinate on every point of graph
这才是图像的transformation
2.先画出y=ln x的图像,然后按1.的步骤做
3.1)（中文表示不清楚）：take e as base and take right hand side and left hand side as your exponent.得到 e^ (-2ln (x-2) = e^10
2).由代数性质（x ^ nm = x^m * x^n）,我们得到e^(-2) * e^(ln (x-2)) = e^10
3).由对数性质（e^ ln(x) = x)得到 e^(-2) * (x-2) = e^10
4).剩下的就简单了,两边同除e^(-2),+2,最后结果是 x = 2 - e^12
本人美国大学数学系研究生,希望答案对你有所帮助.

靠，英语没学好的欲哭无泪啊

第一题 x=2x-4
第二题 大概的图像，与logx样子一样，就是零点是x=2
第三题 e^10=e^(2x-4) 解得x=7

不知道，太深奥了，不要意思