(1)(1/(x-10))+(1/(x-6))=(1/(X-7))+(1/(x-9))(2)((x+1)/(x-2))-((x+2)/(X+3))=(1/(x+7))-(1/(x-6))

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/25 17:05:51
(1)(1/(x-10))+(1/(x-6))=(1/(X-7))+(1/(x-9))(2)((x+1)/(x-2))-((x+2)/(X+3))=(1/(x+7))-(1/(x-6))(1)(1/(

(1)(1/(x-10))+(1/(x-6))=(1/(X-7))+(1/(x-9))(2)((x+1)/(x-2))-((x+2)/(X+3))=(1/(x+7))-(1/(x-6))
(1)(1/(x-10))+(1/(x-6))=(1/(X-7))+(1/(x-9))
(2)((x+1)/(x-2))-((x+2)/(X+3))=(1/(x+7))-(1/(x-6))

(1)(1/(x-10))+(1/(x-6))=(1/(X-7))+(1/(x-9))(2)((x+1)/(x-2))-((x+2)/(X+3))=(1/(x+7))-(1/(x-6))
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)
y'={(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)}(x-10)+{(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)}(x-10)'
y'(10)={(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)}(x-10)'
=x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)
(x=10)

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