集合A ={(x,y)|3/(x-2)=2/(y+1)}集合B={(x,y)|2x-3y-7=0},若全集U={(x,y)|x属于R,y属于R},则B∩CuA=

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集合A={(x,y)|3/(x-2)=2/(y+1)}集合B={(x,y)|2x-3y-7=0},若全集U={(x,y)|x属于R,y属于R},则B∩CuA=集合A={(x,y)|3/(x-2)=2/

集合A ={(x,y)|3/(x-2)=2/(y+1)}集合B={(x,y)|2x-3y-7=0},若全集U={(x,y)|x属于R,y属于R},则B∩CuA=
集合A ={(x,y)|3/(x-2)=2/(y+1)}集合B={(x,y)|2x-3y-7=0},若全集U={(x,y)|x属于R,y属于R},则B∩CuA=

集合A ={(x,y)|3/(x-2)=2/(y+1)}集合B={(x,y)|2x-3y-7=0},若全集U={(x,y)|x属于R,y属于R},则B∩CuA=
3/(x-2)=2/(y+1)化简得
3y+3=2x-4
2x-3y-7=0 (x≠2,y≠-1)
可见B=A∪(2,-1)
所以B∩CuA={(x,y)|x=2,y=-1}

(2,-1)前后化简后一样,但是A中没有(2,-1)