f(x)=2sin(2x+π/6),若x属于[0,π/2] ,求函数f(x)的值域

f(x)=2sin(2x+π/6),若x属于[0,π/2] ,求函数f(x)的值域
f(x)=2sin(2x+π/6),若x属于[0,π/2] ,求函数f(x)的值域

f(x)=2sin(2x+π/6),若x属于[0,π/2] ,求函数f(x)的值域
x∈[0,π/2]
2x+π/6∈[π/6,7π/6]
当2x+π/6=π/2,f(x)有最大值2
当2x+π/6=7π/6,f(x)有最小值-1
所以值域为[-1,2]

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