已知(x+y-1)^2+√x^2+2x+1=0,求实数x,y的值.
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已知(x+y-1)^2+√x^2+2x+1=0,求实数x,y的值.已知(x+y-1)^2+√x^2+2x+1=0,求实数x,y的值.已知(x+y-1)^2+√x^2+2x+1=0,求实数x,y的值.即
已知(x+y-1)^2+√x^2+2x+1=0,求实数x,y的值.
已知(x+y-1)^2+√x^2+2x+1=0,求实数x,y的值.
已知(x+y-1)^2+√x^2+2x+1=0,求实数x,y的值.
即(x+y-1)^2+√ (x+1)^2=0
(x+y-1)^2+|x+1|=0
所以x+y-1=x+1=0
所以
x=-1
y=1-x=2
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