3(2y-1)-2(1-y)=0
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3(2y-1)-2(1-y)=03(2y-1)-2(1-y)=03(2y-1)-2(1-y)=0解3(2y-1)-2(1-y)=06y-3-2+2y=08y=5y=5/83(2y-1)-2(1-y)=
3(2y-1)-2(1-y)=0
3(2y-1)-2(1-y)=0
3(2y-1)-2(1-y)=0
解
3(2y-1)-2(1-y)=0
6y-3-2+2y=0
8y=5
y=5/8
3(2y-1)-2(1-y)=0
即
6y-3-2+2y=0
6y+2y-3-2=0
8y=5
y=5/8
8y=5
y=5/8
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