spss中chi-square检验的自由度的计算公式是什么比如得出的表格是这样：EvaluationsChi-Square(a) 62.500df 9Asymp.Sig..000a 5 cells (10%) have expected frequencies less than 5.The minimum expected cell frequency is 12.0.我的样

spss中chi-square检验的自由度的计算公式是什么比如得出的表格是这样：EvaluationsChi-Square(a) 62.500df 9Asymp.Sig..000a 5 cells (10%) have expected frequencies less than 5.The minimum expected cell frequency is 12.0.我的样
spss中chi-square检验的自由度的计算公式是什么
比如得出的表格是这样：
Evaluations
Chi-Square(a) 62.500
df 9
Asymp.Sig..000
a 5 cells (10%) have expected frequencies less than 5.The minimum expected cell frequency is 12.0.
我的样本是50个,df的9是怎么算的.另外 5 cells (10%) have expected frequencies less than 5.The minimum expected cell frequency is 12.0.less than 5,这里的5是哪里来的?
谢谢您的回答,但是也有50个样本,自由度为49,而出现0cells have expected frequencies less than 5.那么这是说50个被试分为50个类别么.那么怎么能0个类别的期望被试数少于5呢?

spss中chi-square检验的自由度的计算公式是什么比如得出的表格是这样：EvaluationsChi-Square(a) 62.500df 9Asymp.Sig..000a 5 cells (10%) have expected frequencies less than 5.The minimum expected cell frequency is 12.0.我的样
你的被试是50个,但是卡方分析不是依据被试数来的,而是依据类别来的,也就是说这50个被试被你分成了10个类别,计算到最后就是9个自由度了.
5 cells (10%) have expected frequencies less than 5. The minimum expected cell frequency is 12.0.
这是说你有5个类别的期望被试数少于5,而最少的期望数是12.这里的5是卡方分析应该遵循的极限值,如果小于5会影响到结果的准确性.
可以采取的方法是将10类进行合并.