(1)y=x-5x-6.(2)y=9-x .这俩函数的图像怎么画?怎么解的(1)y=x-5x-6.(2)y=9-x .这俩函数的图像怎么画?

x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11 {6(x-y)-7(x+y)=21 {2(x-y)-5(x+y)=-1 (x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5) {(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=? 先化简再求值 x(9x-y)-y(y-x)+(x-y)的平方,其中x=-1,y=2 (x-y)/4+(x+y)/5=1/4 (x+y)/9-(x-y)/3=//2(x-y)/4+(x+y)/5=1/4(x+y)/9-(x-y)/3=//2 解方程组 3(x+y)-2(x-y)=9,5(x+y)+2(x-y)=-1 解方程组:{3(x+y)-2(x-y)=9,5(x+y)+2(x-y)=-1} 已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) 分式的加减:[(x/y-y/x)除以（x+y）+x（1/y-1/x)]除以1+x/y,其中x=5,y=2 化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1 5x=3y,(2x+y)的平方=5x(x+y)+9 9y=3x-(x-1),4(x+y)-(2x+4)=8y （2x+y-1)(2x-y+1)-(3x+y)(3x-y),其中x=5分之1, 解方程组: ｛3x+2y=13 3x-2y=5 ｛x-y/3=x+y/2+1 2x-5y=9 已知x+y=a,2x-y=-2a,求[（x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值 若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值