化简:[1-(sin4x-sin2xcos2x+cos4x)]/sin2x+3sin2x.

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化简:[1-(sin4x-sin2xcos2x+cos4x)]/sin2x+3sin2x.化简:[1-(sin4x-sin2xcos2x+cos4x)]/sin2x+3sin2x.化简:[1-(sin

化简:[1-(sin4x-sin2xcos2x+cos4x)]/sin2x+3sin2x.
化简:[1-(sin4x-sin2xcos2x+cos4x)]/sin2x+3sin2x.

化简:[1-(sin4x-sin2xcos2x+cos4x)]/sin2x+3sin2x.
因为:1-(sinx)^4-(sinx)^2(cosx)^2+(cosx)^4=1-[(sin²x+cos²x)-3sin²xcos²x]
=3sin²xcos²x,
所以:原式=3sin²xcos²x/sin²x+3sin²x=3cos²x+3sin²x=3(cos²x+sin²x)=3

2xcos2x+cos4x)]/sin2x+