=2∫[u²/(1+u)]du=2∫[(u-1)+1/(u+1)]du 这一步是怎么求出来的.

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=2∫[u²/(1+u)]du=2∫[(u-1)+1/(u+1)]du这一步是怎么求出来的.=2∫[u²/(1+u)]du=2∫[(u-1)+1/(u+1)]du这一步是怎么求出来

=2∫[u²/(1+u)]du=2∫[(u-1)+1/(u+1)]du 这一步是怎么求出来的.
=2∫[u²/(1+u)]du=2∫[(u-1)+1/(u+1)]du 这一步是怎么求出来的.

=2∫[u²/(1+u)]du=2∫[(u-1)+1/(u+1)]du 这一步是怎么求出来的.
u²/(1+u)=(u²-1+1)/(1+u)=u-1+1/(u+1)