4m^2-2mn-2n^2+4m-7n-3怎么分解因式

m-n=7 mn=-5求(3m+5n+4mn)-(2n-4n+6mn) (2m+n)(4m^2-2mn+n^2) (m-n)(m^5+m^4n+m^3n^2+m²n^3+mn^4+n^5) (7m^2-4mn-n^2)-2(2m^2-mn+2n^2)计算. (7m²-4mn-n²)-(3m²-mn+2n²)求解 [(m+n)^2-4mn][(m-n)^2+4mn]+2(mn)^2 3(m^2n+mn)-4(mn-2m^2n)+mn.要有过程 已知m-n=4,m、n互为倒数求(-2mn+2m+3n)-(3mn+2n-2m)-(m+4m+mn)的值 2m(m-n)^2-4n(n-m)^3 （分解因式）-7m(m-n)^3+21mn(n-m)^2 (分解因式）快 已知m-n=2,mn=1,求多项式(-2mn+2mn+3n)-(3mn+2n-2m)-(m+4n+mn)的值 已知m-n=2,mn=1,求多项式(-2mn+2mn+3n)-(3mn+2n-2m)-(m+4n+mn)的值 已知m-n=4,mn=2,求多项式（-2mn+2m+3n)-(3mn+2n-2n)-(m+4n+mn)的值 4-m²n²+2mn 已 知m-n=4,mn=-1,求：（-2mn+2m+3n)-(3mn+2n-2n)-(m+4n+mn)的值 已知m-n=4,mn=2,求多项式（-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值. 已知m-n=4,mn=-1,求（-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn）的值. 若m-n=4,mn=-1,求（-2mn+2m+3n）-（3mn+2n-2m）-（m+4n+mn） 若m-n=4,mn=-1求(9-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)