lg6/lg12=a 则 lg12/lg24=

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lg6/lg12=a则lg12/lg24=lg6/lg12=a则lg12/lg24=lg6/lg12=a则lg12/lg24=lg6/lg12=a(lg2+lg3)/(2lg2+lg3)=alg2+l

lg6/lg12=a 则 lg12/lg24=
lg6/lg12=a 则 lg12/lg24=

lg6/lg12=a 则 lg12/lg24=
lg6/lg12=a
(lg2+lg3)/(2lg2+lg3)=a
lg2+lg3=a(2lg2+lg3)
lg2+lg3=2alg2+alg3
lg2-2alg2=alg3-lg3
(1-2a)lg2=(a-1)lg3
lg2/lg3=(a-1)/(1-2a)
lg12/lg24=(2lg2+lg3)/(3lg2+lg3)
=[(2lg2+lg3)×1/lg3]/[(3lg2+lg3)×1/lg3]
=(2lg2/lg3+1)/(3lg2/lg3+1)
=[2(a-1)/(1-2a)+1]/[3(a-1)/(1-2a)+1]
=[2(a-1)/(1-2a)+(1-2a)/(1-2a)]/[3(a-1)/(1-2a)+(1-2a)/(1-2a)]
=[(2a-2+1-2a)/(1-2a)]/[(3a-3+1-2a)/(1-2a)]
=[-1/(1-2a)]/[(a-2)/(1-2a)]
=[-1/(1-2a)]×[(1-2a)/(a-2)]
=-1/(a-2)