y=sin(x+1) 求y'(0)

来源:学生作业帮助网 编辑:六六作业网 时间:2024/07/08 23:03:07
y=sin(x+1)求y''(0)y=sin(x+1)求y''(0)y=sin(x+1)求y''(0)y''=cos(x+1)*(x+1)''=cos(x+1)所以y''(0)=cos(0+1)=cos1

y=sin(x+1) 求y'(0)
y=sin(x+1) 求y'(0)

y=sin(x+1) 求y'(0)
y'=cos(x+1)*(x+1)'=cos(x+1)
所以y'(0)=cos(0+1)=cos1