lingo max=4820*(1-0.1*4*a1)*297*(1+a1)*1000+320*(1-0.1*27*a2)*720*(1+a2)*1000+210*(1-0.1*11*a3-0.1*a4)*(1+a3)*1050*1000+70*(1-0.1*4*a4-0.1*4*a3)*815*(1+a4)*1000;4820*(1-0.1*4*a1)*0.01*4+320*(1-0.1*27*a2)*0.01*80+210*(1-0.1*11*a3-0.1*a4)*0.01*35+70*(1

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lingomax=4820*(1-0.1*4*a1)*297*(1+a1)*1000+320*(1-0.1*27*a2)*720*(1+a2)*1000+210*(1-0.1*11*a3-0.1*a4

lingo max=4820*(1-0.1*4*a1)*297*(1+a1)*1000+320*(1-0.1*27*a2)*720*(1+a2)*1000+210*(1-0.1*11*a3-0.1*a4)*(1+a3)*1050*1000+70*(1-0.1*4*a4-0.1*4*a3)*815*(1+a4)*1000;4820*(1-0.1*4*a1)*0.01*4+320*(1-0.1*27*a2)*0.01*80+210*(1-0.1*11*a3-0.1*a4)*0.01*35+70*(1
lingo
max=4820*(1-0.1*4*a1)*297*(1+a1)*1000+320*(1-0.1*27*a2)*720*(1+a2)*1000+210*(1-0.1*11*a3-0.1*a4)*(1+a3)*1050*1000+70*(1-0.1*4*a4-0.1*4*a3)*815*(1+a4)*1000;
4820*(1-0.1*4*a1)*0.01*4+320*(1-0.1*27*a2)*0.01*80+210*(1-0.1*11*a3-0.1*a4)*0.01*35+70*(1-0.1*4*a4-0.1*4*a3)*0.01*25

lingo max=4820*(1-0.1*4*a1)*297*(1+a1)*1000+320*(1-0.1*27*a2)*720*(1+a2)*1000+210*(1-0.1*11*a3-0.1*a4)*(1+a3)*1050*1000+70*(1-0.1*4*a4-0.1*4*a3)*815*(1+a4)*1000;4820*(1-0.1*4*a1)*0.01*4+320*(1-0.1*27*a2)*0.01*80+210*(1-0.1*11*a3-0.1*a4)*0.01*35+70*(1
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lingo中求最小值问题model:max=x1+x2;-1 2用Lingo软件求解:max z= c^T*x+0.5*x^T*Q*x; s.t.-1 数学模型lingo求助(1)用LINGO求解:输入文件:max=3*x1+2*x2;2*x1+3*x2<14;x1+0.5*x2<4.5;@gin(x1);@gin(x2);求解得到输出(只列出需要的结果): lingo 0-1规划程序问题Max=∑xi (i∈E)s.t Hq=0 (H为VxE的已知矩阵)-1000xi lingo软件求教max=1/2*x1*x2*@sin(x4)+1/2*x2*x3*@sin(120-x4);x4>0;x4 一道lingo的小小小题目:max:f(x1,x2=100*(x1^2-x2)^2+(1-x1)^2,s.t.-2.048 整数规划LINGO求解,max R=20X + 5Y2X + 3Y 用LINGO软件求解非线性规划:max z=x1^2-x2 s.t.{x1^2+x2^2 lingo求解最优化问题w=max∑Xi*P*t,约束条件是∑Xi*Si LINGO编程问题,代码在下面,运行说第三行有错误max=2*x1+x2;st5*x2 请问:在lingo上要怎么输以下式子MAX=7*x1+5*x23*x1+2*x2 max z=5*x1+2*x2^2+x3^2 x1+4*x2+3*x3=6 x(i)>=0,i=1,2,3 用lingo怎么解 lingo 最优化-混合整数和0/1规划请问用lingo计算一个:15 4max ∑ ∑[pgen(t)(i)-u(i)(t)*(1-u(i)(t-1)*pstart(i)]t=1 i=1s.t tstart(i)>=[n/a,5,n/a,n/a]tstart(i)=0i=1pgen(i)(t)=0 (0 lingo软件的模型的建立求高手指点一下下面的方程式在lingo软件中该如何编写模型,能帮我直接编写一套完整可用的最好.谢了~! Max=9*x1+3*x2+1*x3+1*x4+0.5*x5S.t:1.0x1+1.0x2+1.0x3+1.0x4+1.0x5 lingo程序错误1017model:sets:question(/1..i/):x,y;endsetsinit:x(1)=0;y(1)=0;endinit[obj] max=@sum(link(i,j):c(i))@for(question:(min(@sqrt((x(i)-x(i1))^2+(y(i)-y(j))^2))>=z););@for(question:(max(@sqrt((x(i)-x(i1))^2+(y(i)-y(j))^2)) 关于Lingo变量的限制如何在Lingo的目标函数限制条件中,限制变量只能取确切的几个值.如:max=x1+x2*x3+x4x1+x2 max=a if(max Lingo 出错model:max=0.0043*X1+0.0027*X2+0.0025*X3+0.0022*X4+0.0045*X5X2+X3+x4>=4000.6*X1+0.6*X2-0.4*X3-0.4*X4+3.6*X5