limx趋向无穷[(x^2+1)/(x+1)]-(ax+b)=1 求a,b

来源：学生作业帮助网编辑：六六作业网时间：2024/10/05 15:02:25

limx趋向无穷[(x^2+1)/(x+1)]-(ax+b)=1求a,blimx趋向无穷[(x^2+1)/(x+1)]-(ax+b)=1求a,blimx趋向无穷[(x^2+1)/(x+1)]-(ax+

limx趋向无穷[(x^2+1)/(x+1)]-(ax+b)=1 求a,b
limx趋向无穷[(x^2+1)/(x+1)]-(ax+b)=1 求a,b