(x+2)-(x+1)/(x+1)(x+2)=m/x+1 - n/x+2,mn为常数,则mn=?

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(x+2)-(x+1)/(x+1)(x+2)=m/x+1-n/x+2,mn为常数,则mn=?(x+2)-(x+1)/(x+1)(x+2)=m/x+1-n/x+2,mn为常数,则mn=?(x+2)-(x

(x+2)-(x+1)/(x+1)(x+2)=m/x+1 - n/x+2,mn为常数,则mn=?
(x+2)-(x+1)/(x+1)(x+2)=m/x+1 - n/x+2,mn为常数,则mn=?

(x+2)-(x+1)/(x+1)(x+2)=m/x+1 - n/x+2,mn为常数,则mn=?
(x+2)-(x+1)/(x+1)(x+2)=m/x+1 - n/x+2
(x+2)/(x+1)(x+2)-(x+1)/(x+1)(x+2)=m/x+1 - n/x+2
1/(x+1)-1/(x+2)=m/x+1 - n/x+2
所以m=n=1
mn=1