(x-1)(x-2)(x-3)(x-4)-120的解法.
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(x-1)(x-2)(x-3)(x-4)-120的解法.(x-1)(x-2)(x-3)(x-4)-120的解法.(x-1)(x-2)(x-3)(x-4)-120的解法.楼主是:(x-1)(x-2)(x
(x-1)(x-2)(x-3)(x-4)-120的解法.
(x-1)(x-2)(x-3)(x-4)-120的解法.
(x-1)(x-2)(x-3)(x-4)-120的解法.
楼主是:(x-1)(x-2)(x-3)(x-4)>120吧
(x-3)(x-2)=x²-5x+6
(x-1)(x-4)=x²-5x+4
设 t=x²-5x+4
t(t+2)>120
t²+2t-120>0
(t+12)(t-10)>0
t>10 或者 t10 或者 x²-5x+4
直接把括号中的X逐个相乘,最后因该是X的4次方减120.
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