(2a-b)(2a+1/3)=4a^2-1/9,则b=＿
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(2a-b)(2a+1/3)=4a^2-1/9,则b=＿(2a-b)(2a+1/3)=4a^2-1/9,则b=＿(2a-b)(2a+1/3)=4a^2-1/9,则b=＿(2a-b)(2a+1/3)=4
(2a-b)(2a+1/3)=4a^2-1/9,则b=＿
(2a-b)(2a+1/3)=4a^2-1/9,则b=＿
(2a-b)(2a+1/3)=4a^2-1/9,则b=＿
(2a-b)(2a+1/3)
=4a^2-1/9
=(3a-1/3)(2a+1/3)
所以b=1/3
(2a-b)(2a+1/3)=4a^2-1/9
2a*2a=4a^2
常数项是
-b/3=-1/9
所以b=1/3
验算
-1/3*2a+1/3*2a=0
所以b=1/3
望采纳，谢谢