x+y=2 y+z=1 z+x=5
来源:学生作业帮助网 编辑:六六作业网 时间:2025/02/07 02:06:09
x+y=2y+z=1z+x=5x+y=2y+z=1z+x=5x+y=2y+z=1z+x=5三个方程相加得:2(x+y+z)=2+1+5,x+y+z=4x+y+z=4式减一式得:z=2同理的:x=3,y
x+y=2 y+z=1 z+x=5
x+y=2 y+z=1 z+x=5
x+y=2 y+z=1 z+x=5
三个方程相加得:2(x+y+z)=2+1+5,x+y+z=4
x+y+z=4式减一式得:z=2
同理的:x=3,y=-1
即:x=3,y=-1,z=2
x+y=2 .......(1)
y+z=1..........(2)
z+x=5 ........(3)
则(1)-(2)得:x-z=1......(4)
(3)+(4)得:2x=6
解得:x=3
把x=3代入(1)得:y=-1
把x=3代入(3)得:z=2
(1)x+y=2
(2) y+z=1
(3) z+x=5
(4)=x-z=1【(1)-(2)】
(4)+(3)得到 2x=6 x=3 y=-1 z=2
已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=?
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
(x+y-z)(x-y+z)=
{x+y-z=11 y+z-x=5 z+x-y=1
{x+y-z=11,x-y-z=-5,x-y+z=1
x/2=y/3=z/5 x+3y-z/x-3y+z
用行列式的性质证明:y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证?
(x-2y+z)(x+y-2z)分之(y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之(x-z)(y-z)=?第三部分那个是 (y+z-2x)(x-2y+z)分之(x-z)(y-z)
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
x+y+z=6 x+2y+3z=14 y+1=z
x+Y+Z=1 X+3Y+7Z=-1 X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2
方程组 (1) x+2y-3z=12 x-3y+2z= - 13 x-y-z=0 (2) x+ y=z 5x-y+z=18 2x+5y+3z= -1
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知:x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值.
x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值