1/2(t-4)(4t-16)+1/2[(4t-16)+(t-1)]×3-1/2(t-1)(t-1)=(麻烦用笔写下来,要完整的过程,谢谢!)
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1/2(t-4)(4t-16)+1/2[(4t-16)+(t-1)]×3-1/2(t-1)(t-1)=(麻烦用笔写下来,要完整的过程,谢谢!)1/2(t-4)(4t-16)+1/2[(4t-16)+(
1/2(t-4)(4t-16)+1/2[(4t-16)+(t-1)]×3-1/2(t-1)(t-1)=(麻烦用笔写下来,要完整的过程,谢谢!)
1/2(t-4)(4t-16)+1/2[(4t-16)+(t-1)]×3-1/2(t-1)(t-1
)=(麻烦用笔写下来,要完整的过程,谢谢!)
1/2(t-4)(4t-16)+1/2[(4t-16)+(t-1)]×3-1/2(t-1)(t-1)=(麻烦用笔写下来,要完整的过程,谢谢!)
1/2(t-4)(4t-16)+1/2[(4t-16)+(t-1)]×3-1/2(t-1)(t-1)=
1/2(t-4)(4t-16)+3/2(4t-16)+3/2(t-1)-1/2(t-1)(t-1)=
1/2(4t-16)[(t-4)+3]+1/2(t-1)[3-(t-1)]=
1/2(4t-16)(t-1)+1/2(t-1)(4-t)=
4/2(t-4)(t-1)-1/2(t-1)(t-4)=
3/2(t-4)(t-1)
(2t+3)(2t-)-(4t+1)(t-9)
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4t^-8t+5-3t^+6t-2 其中t=2/1
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5t-3≤4t-1 7+2t>6+3t 3+t
画出下列信号的波形1)f(t)=tu(t); 2)f(t)=t[u(t)-u(t-2)]; 3)f(t)=(t-1)u(t-1); 4)f(t)=sint/t画出图形~
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t小于0,求y=(t^2-4t+1)/t的最大值
t>0,y=(t^2-4t+1)/t最小值
t>0,y=(t^2-4t+1)/t的最小值是
已知t>0,则函数y=(t^2-4t+1)/t的最小值为
[T,Y]=ode45(@rigid,[0 1],[rand(15,1)]);plot(T,Y(:,1),'-',T,Y(:,2),'-.',T,Y(:,3),'.',T,Y(:,4),'-',T,Y(:,5),'-.',T,Y(:,6),'.',T,Y(:,7),'-',T,Y(:,8),'-.',T,Y(:,9),'.',T,Y(:,10),'-',T,Y(:,11),'-.',T,Y(:,12),'-.',T,Y(:,13),'.',T,Y(:,14),'-',T,Y(:,15),'.')
matlab中怎么对下面的程序进行二维插值并画出三维视图呢?[x,y]=meshgrid(-2:1:2);t=2;Z=[(sin(t))^3 t^2 sin(t) cos(t) (sin(t))^2;t^2 sin(t) (cos(t))^4 cos(t) (sin(t))^2;t sin(t) cos(t) t^2 (sin(t))^2;sin(t) (cos(t))^3 t^2 (sin(t))^2