已知[(3x-4)/(x-3)]/[(1/(x-3)]=A,a为常数,且A为关于x的整式,求a的值

已知[(3x-4)/(x-3)]/[(1/(x-3)]=A,a为常数,且A为关于x的整式,求a的值
已知[(3x-4)/(x-3)]/[(1/(x-3)]=A,a为常数,且A为关于x的整式,求a的值

已知[(3x-4)/(x-3)]/[(1/(x-3)]=A,a为常数,且A为关于x的整式,求a的值
原式=（3x-4）/(x-3)乘上(x-3)
所以А=3x-4

原式为:

(3X-4)
------
(X-3) (3X-4) 1
------------ = A →→ -------- = A * ----- →→ 3X-4 = A
1 (X-3) (X-3)
-------
(x-3)
∴ A = 3X-4