求lim{下面(x属于0)}(1-cosx)/ln(1+x^2)的极限怎么算?
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求lim{下面(x属于0)}(1-cosx)/ln(1+x^2)的极限怎么算?求lim{下面(x属于0)}(1-cosx)/ln(1+x^2)的极限怎么算?求lim{下面(x属于0)}(1-cosx)
求lim{下面(x属于0)}(1-cosx)/ln(1+x^2)的极限怎么算?
求lim{下面(x属于0)}(1-cosx)/ln(1+x^2)的极限怎么算?
求lim{下面(x属于0)}(1-cosx)/ln(1+x^2)的极限怎么算?
lim(x→0)(1-cosx)/ln(1+x^2)
[洛必达法则]
=lim(x→0)sinx/[(2x)/(1+x^2)]
=lim(x→0)[sinx/2x]*(1+x^2)
[sinx和x是等价无穷小量]
=1/2*1
=1/2
1-cosx~1/2x^2
1/2
1/2