Let f(x)=-4X^2+8X+13 Find g'(3) Show that the linear approximation to g(3+△x) always gives an answer which is too large,regardless of whether △x is positive or negative.Interpret your answer geometrically by drawing graph of g and its tangent lin
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Let f(x)=-4X^2+8X+13 Find g'(3) Show that the linear approximation to g(3+△x) always gives an answer which is too large,regardless of whether △x is positive or negative.Interpret your answer geometrically by drawing graph of g and its tangent lin
Let f(x)=-4X^2+8X+13 Find g'(3) Show that the linear approximation to g(3+△x) always gives an answer which is too large,regardless of whether △x is positive or negative.Interpret your answer geometrically by drawing graph of g and its tangent line when x=3.
这道题的意思,我没有完全理解,
Let f(x)=-4X^2+8X+13 Find g'(3) Show that the linear approximation to g(3+△x) always gives an answer which is too large,regardless of whether △x is positive or negative.Interpret your answer geometrically by drawing graph of g and its tangent lin
设 f(x)=-4X^2+8X+13 ,求g'(3)并证明 g(3+△x)的极限总是无穷大,不管△x 是正还是负.画出函数g的曲线图,和当x=3时的切线来解释你的答案.
大概是这样 自己再斟酌一下