已知|ab-2|+(b-l)的平=0,求ab分之1+(a+1)x(b+1)分之1+(a+2)x(b+2)+…+(a+2010)x(b+2010)的值.

已知|ab-2|+(b-l)的平=0,求ab分之1+(a+1)x(b+1)分之1+(a+2)x(b+2)+…+(a+2010)x(b+2010)的值.
已知|ab-2|+(b-l)的平=0,求ab分之1+(a+1)x(b+1)分之1+(a+2)x(b+2)+…+(a+2010)x(b+2010)的值.

已知|ab-2|+(b-l)的平=0,求ab分之1+(a+1)x(b+1)分之1+(a+2)x(b+2)+…+(a+2010)x(b+2010)的值.
由题意得ab-2=0,ab=2,b-1=0,b=1 a=2
代入式子等于=1/1*2+1/2*3+1/3*4.+1/2010*2011+1/2011*2012
=(1-1/2）+（1/2-1/3)+(1/3-1/4)+.+(1/2010-1/2011)+(1/2011-1/2012)
=1-1/2012=2011/2012
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|ab-2|+(b-l)²=0
所以：ab-2=0,b-1=0
ab=2,b=1
a=2

1/ab+(a+1)x(b+1)分之1+(a+2)x(b+2)分之1+…+(a+2010)x(b+2010)分之1
=(1-1/2)+(3)x(2)分之1+(4)x(3)分之1+…+(2012)x(2011)分之1
=1-1/2+(1/2-...

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|ab-2|+(b-l)²=0
所以：ab-2=0,b-1=0
ab=2,b=1
a=2

1/ab+(a+1)x(b+1)分之1+(a+2)x(b+2)分之1+…+(a+2010)x(b+2010)分之1
=(1-1/2)+(3)x(2)分之1+(4)x(3)分之1+…+(2012)x(2011)分之1
=1-1/2+(1/2-1/3)+（1/3-1/4)+……+(1/2011-1/2012)
=1+1/2-1/3+1/3-1/4+……+1/2011-1/2012
=1-1/2012
=2011/2012

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