求极限(sin^2)n/n+1
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/23 17:25:45
求极限(sin^2)n/n+1求极限(sin^2)n/n+1求极限(sin^2)n/n+1|sinn|如果n趋于无穷的话,由于分子是有界函数,分母趋于无穷大,则整个极限趋于0
求极限(sin^2)n/n+1
求极限(sin^2)n/n+1
求极限(sin^2)n/n+1
|sin n|
如果n趋于无穷的话,由于分子是有界函数,分母趋于无穷大,则整个极限趋于0
求极限(sin^2)n/n+1
求极限lim(1/n)*[(sin(pi/n)+sin(2pi/n)+.+sin(n*pi/n)] n->无穷
求极限:lim((2n∧2-3n+1)/n+1)×sin n趋于无穷
求极限(sin(2/n)+cos(3/n))^(-n)
当n趋于无穷时,求[sin(π/n)/(n+1)+sin(2π/n)/(n+1/2)+.sinπ/(n+1/n)]的极限
sin(pai/n)^2求极限收敛性
求极限 lim sin pi(n^2+1)^(1/2)
求极限 lim sin pi*(n^2+1)^(1/2)
求极限lim(n→无穷) (三次根号下n^2)*sin /(n+1)
求极限lim2^(n-1)sin(x/2^n) n趋近于无穷
[1sin(1/n)]/[n²+n+1]+[2sin(2/n)]/[n²+n+2]+……+[nsin(n/n)]/[n²+n+n]求n趋于无穷大时极限?
n趋于正无穷求极限n^2*ln[n*sin(1/n)]答案是-1/6
求sin(√(n+1))-sin(√n),当n趋向无穷的极限
高数求极限n趋于无穷大时,lim (1/n - sin(1/n))/ (1/n^2),lim (1/n - sin(1/n))/ (1/n^3)这一式子呢求极限n趋于无穷大时,lim (1/n - sin(1/n))/ (1/n^2),lim (1/n - sin(1/n))/ (1/n^3)这一式子呢?
求极限lim n→∞ 根号n乘以sin n 除以n+1
(√n sin n )/ (n+1) 求当n趋近正无穷的时候的极限.
求极限 lim Sin[pi*√(n^2+1)] n→∞
极限 lim(x-->无穷)(1/n sin(n)+1/n sin(1/n)+nsin(1/n))求极限lim(x-->无穷)(1/n sin(n)+1/n sin(1/n)+nsin(1/n))