先化简,再求值:[(x-2)/(x+2)+4x/(x²-4)]÷1/(x²-4)其中,x=-3

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先化简,再求值:[(x-2)/(x+2)+4x/(x²-4)]÷1/(x²-4)其中,x=-3先化简,再求值:[(x-2)/(x+2)+4x/(x²-4)]÷1/(x&#

先化简,再求值:[(x-2)/(x+2)+4x/(x²-4)]÷1/(x²-4)其中,x=-3
先化简,再求值:[(x-2)/(x+2)+4x/(x²-4)]÷1/(x²-4)其中,x=-3

先化简,再求值:[(x-2)/(x+2)+4x/(x²-4)]÷1/(x²-4)其中,x=-3
=[(x-2)/(x+2)+4x/(x²-4)]×(x²-4)
=(x-2)/(x+2)×(x²-4) +4x/(x²-4) ×(x²-4)
=(x-2)²+4x
=x²+4
当x=-3时
原式=9+4=13

[(x-2)/(x+2)+4x/(x²-4)]÷1/(x²-4)=(x-2)^2+4x=x^2+4代入x=-3得: 原式=13

[(x-2)/(x+2)+4x/(x²-4)]÷1/(x²-4)
=(x-2)/(x+2)*(x²-4)+4x/(x²-4)*(x²-4)
=(x-2)^2+4x
=x^2+4
(-3)^2+4
=9+4
=13

[(x-2)/(x+2)+4x/(x²-4)]÷1/(x²-4)
=((x-2)/(x+2))*(x^2-4)+(4x/(x^2-4))*(x^2-4)
=((x-2)/(x+2))*(x+2)(x-2)+(4x/(x^2-4))*(x^2-4)
=(x-2)^2+4x
=x^2-4x+4+4x
=x^2+4
=(-3)^2+4
=13

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