log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8( 8^(2/3) )怎么得出来的?
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log4(3)-log4(12)-log8(4)=log4(3/12)-log8(8^(2/3))log8(8^(2/3))怎么得出来的?log4(3)-log4(12)-log8(4)=log4(3
log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8( 8^(2/3) )怎么得出来的?
log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8( 8^(2/3) )怎么得出来的?
log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8( 8^(2/3) )怎么得出来的?
这个问题是这样的
4=2²=(2^3)^(2/3)=8^(2/3)
所以 log8( 8^(2/3))=2/3
前面的是对数运算法则 loga M-loga N=loga (M/N)
log4
求证:log4 3*log4 5
(log2 5+log4 125)log3 2/ log根号3 5
解方程log4(3x+1)=log4x+log(3+x)最后是log4(3+x)
2^log4(3)
log4(3x-2)
2^log4^3=?
(1/4)^log4(3)
log4^27×log(8)25×log9^5
log4^27×log(8)25×log9^5
log (log2)^2 - (log4)(log20) + (log20)^2
如题{log(2√2) - 3log√3 - 3} / {log9 - log4 + 4}
log4 (x+3)+log(1/4) (x-3)=log(1/4) (x-1)+log4 (2x+1)的解集,
log4 243 - log8 729=?log4 12 - log2 6=?
log4 3 和log4/3 3/4 谁大
解方程log4 x+1/log4 x=10/3
[log3(4)+log根下3(2)][log2(9)+log4(根3)]
log 底数是4根号3 真数是81 log4根号3 81 最好有分析!