x^2-4y^2/x^2+4xy+4y^2-x/x+2y,其中x=-4,y=-3x^2-4y^2/(x^2+4xy+4y^2)-x/(x+2y),其中x=-4,y=-3
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x^2-4y^2/x^2+4xy+4y^2-x/x+2y,其中x=-4,y=-3x^2-4y^2/(x^2+4xy+4y^2)-x/(x+2y),其中x=-4,y=-3x^2-4y^2/x^2+4xy
x^2-4y^2/x^2+4xy+4y^2-x/x+2y,其中x=-4,y=-3x^2-4y^2/(x^2+4xy+4y^2)-x/(x+2y),其中x=-4,y=-3
x^2-4y^2/x^2+4xy+4y^2-x/x+2y,其中x=-4,y=-3
x^2-4y^2/(x^2+4xy+4y^2)-x/(x+2y),其中x=-4,y=-3
x^2-4y^2/x^2+4xy+4y^2-x/x+2y,其中x=-4,y=-3x^2-4y^2/(x^2+4xy+4y^2)-x/(x+2y),其中x=-4,y=-3
(x^2-4y^2)/(x^2+4xy+4y^2)-x/(x+2y)
=[(x+2y)(x-2y)]/(x+2y)^2-x/(x+2y)
=(x-2y)/(x+2y)-x/(x+2y)
=-2y/(x+2y)
=6/-10
=-3/5
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(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
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(x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy)
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(x^2+2xy+y^2-4xy)*(x^2-2xy+y^2+4xy)
已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值?
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计算:4xy-(x+y)^2/xy(x+y)(x-y)÷x^2+xy-2y^2/x^2y+2xy^2
化简2(x²y+xy)-3(x²y-xy)-4x²y
(-3x^y+2xy)-( )=4x^+xy
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x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x²
(-x-2y)(x²-2xy+4y²)
-2x³y+4x²y-2xy
计算:[(x-y)^2-(x+y)^2]/(-4xy)=