m²n²-2m²n+m²
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m²n²-2m²n+m²m²n²-2m²n+m²m²n²-2m²n+m²解原式=
m²n²-2m²n+m²
m²n²-2m²n+m²
m²n²-2m²n+m²
解 原式=m²（n²-2n）+m²
=m²（n²-2n+1)
=m²（n-1)²
=m²(n²-2n+1)
=m²(n-1)²
m²n²-2m²n+m²
=m²（n²-2n+1)
=m²（n-1)²
m²n²-2m²n+m²
＝m^2(n^2-2n_1)
=m^2(n-1)^2
提出m²
所以 原式= m²(n²-2n+1)=m²（n-1）²