8(x^2+2x)/x^2-1+3(x^2-1)/x^2+2x=11

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8(x^2+2x)/x^2-1+3(x^2-1)/x^2+2x=118(x^2+2x)/x^2-1+3(x^2-1)/x^2+2x=118(x^2+2x)/x^2-1+3(x^2-1)/x^2+2x=

8(x^2+2x)/x^2-1+3(x^2-1)/x^2+2x=11
8(x^2+2x)/x^2-1+3(x^2-1)/x^2+2x=11

8(x^2+2x)/x^2-1+3(x^2-1)/x^2+2x=11
设(x^2+2x)/(x^2-1) = t...(1)
原式就变成了 8t + 3/t =11
解得 t=1 或者 t=3/8
再代回(1)式
解得 x=-1/2 或者 x=-3 或者 x=-1/5

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