{3x-2y=-1,3x-4y=-5
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{3x-2y=-1,3x-4y=-5{3x-2y=-1,3x-4y=-5{3x-2y=-1,3x-4y=-5你把两个等式一减,即3x-2y-(3x-4y)=-1-(-5)拆括号,运算2y=4y=2把这
{3x-2y=-1,3x-4y=-5
{3x-2y=-1,3x-4y=-5
{3x-2y=-1,3x-4y=-5
你把两个等式一减,即
3x-2y-(3x-4y)=-1-(-5)拆括号,运算
2y=4 y=2 把这个带进一个等式就是单项未知数解啦,很简单的x=1喽
好的话帮忙给个满意答案称号啊,俺们任务中,呵呵
顺便问一句,你不是再赶五一作业吧?
3X-2Y=-1 (1)
3X-4Y=-5 (2)
(1)-(2) 3X-2Y-3X-(-4Y)=4 所以2Y=4 Y=2
将Y=2代入(1)得 3X-4=-1 3X=3 X=1
所以 X=1
Y=2
两式相减,得到答案,x=1 ,y=2
X =1y =2
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