2x-3y=0,x+2y=3

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2x-3y=0,x+2y=32x-3y=0,x+2y=32x-3y=0,x+2y=32x-3y=0(1)x+2y=3(2)(2)×2-(1)4y+3y=6-07y=6y=6/7x=3-2y=9/7由第

2x-3y=0,x+2y=3
2x-3y=0,x+2y=3

2x-3y=0,x+2y=3
2x-3y=0 (1)
x+2y=3 (2)
(2)×2-(1)
4y+3y=6-0
7y=6
y=6/7
x=3-2y=9/7

由第二个式子，x=3-2y
带入第一个式子，得2（3-2y）-3y=0
所以解得y=6/7
所以x=3-2y=9/7

2x-3y=0 (1)
x+2y=3 (2)
(2)式*2-(1)式
7y=6
y=6/7
代入(1)得
x=9/7

y=6/7
x=9/7

用加消去法就行了

X=9/7;Y=6/7

2x-3y=0 1式
x+2y=3 2式
2式*2得
2x+4y=6 3式
3式-1式得
7y=6
y=6/7
把y=6/7代人2式得
x+2*6/7=3
x=3-12/7
x=9/7

2x-3y=0 (1)
x+2y=3 (2)
(2)*2-(1)
y=6/7
代入（1）
x=9/7

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