5x+y+z=1 2x-y+2z=1 x+5y-z=4三元一次方程求解

{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2 已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=? 已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值 已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值 x+y+z=6 x+2y+3z=14 y+1=z x+Y+Z=1 X+3Y+7Z=-1 X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2 方程组 (1) x+2y-3z=12 x-3y+2z= - 13 x-y-z=0 (2) x+ y=z 5x-y+z=18 2x+5y+3z= -1 1、y-x/x²-y²2、(x-y)(y-z)(z-x)/(z-y)(y-x)(x-z) 若|x+3|+|y-2|+|2×z+1|=0求(x×z-y×z)(y-x+z)的值 5x+y+z=1 2x-y+2z=1 x+5y-z=4 x+2y+z=1 x+y+2z=2 2x+y+z=5 x-y+z=-1 5x+2y-z=6 4x-3y+2z=-5 3x-y+2z=-1 4x+y+z=5 x-2y-z=-2 x+y+z=2 x-3y+2z=1 2x+2y+z+5 要具体步骤.. {x+y+z=1 {x+3y+7z=-1 {x+5y+8z=2 {x+y+z=1 x-2y+3z=5 2x-3y-3z=-8 x+y+z=-1 4x-2y+3z=5 y-z=8-2x x+y+z=-5,3x+y+z=1,4x+3y+2z=-2快