计算:(4x^2-y^2)÷4x^2-4xy y^2/2x-y

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/26 01:17:51
计算:(4x^2-y^2)÷4x^2-4xyy^2/2x-y计算:(4x^2-y^2)÷4x^2-4xyy^2/2x-y计算:(4x^2-y^2)÷4x^2-4xyy^2/2x-y(4x^2-y^2)

计算:(4x^2-y^2)÷4x^2-4xy y^2/2x-y
计算:(4x^2-y^2)÷4x^2-4xy y^2/2x-y

计算:(4x^2-y^2)÷4x^2-4xy y^2/2x-y
(4x^2-y^2)÷4x^2-4xy y^2/2x-y
=(2x+y)(2x-y)÷ (2x-y)^2/(2x-y)
=2x+y
在右上角点击【评价】,然后就可以选择【满意,问题已经完美解决】了.

4x^2-4xy+y^2/2x+y÷(4x^2-y^2)
=(2x-y)^2/(2x+y)*1/(2x+y)(2x-y)
=(2x-y)/(2x+y)^2