根号下a²-b²+b^4+1/4=0 问a²和b²是多少

根号下a²-b²+b^4+1/4=0 问a²和b²是多少
根号下a²-b²+b^4+1/4=0 问a²和b²是多少

根号下a²-b²+b^4+1/4=0 问a²和b²是多少
√（a²-b²+b^4+1/4）=0
那么a²+（b^4-b²+1/4）=0
a²+(b²-1/2)²=0
∴a²=0且b²-1/2=0
∴a²=0,b²=1/2